SOLUTION: solve log 4x = log(x+3)+log 2 for x

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Question 823746: solve log 4x = log(x+3)+log 2 for x
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi,

log 4x = log(x+3)+log 2    |

log 4x = log 2(x+3)

   4x = 2(x+3)

   4x = 2x + 6

   2x = 6

    x = 3