SOLUTION: If 53 times 118 = (53 times 100)+ ( n times 18), what would n be? This subject is math: distributive property

Algebra ->  Average -> SOLUTION: If 53 times 118 = (53 times 100)+ ( n times 18), what would n be? This subject is math: distributive property       Log On


   

Question 823611: If 53 times 118 = (53 times 100)+ ( n times 18), what would n be?
This subject is math: distributive property

Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
53*118=53*100+18n
6254=5300+18n
6254-5300=18n
954=18n
954/18=n
53=n