SOLUTION: Log2^(x-3)=2-log2^x

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Question 823455: Log2^(x-3)=2-log2^x
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
  • What are you/we supposed to do with this??
  • I suspect that the equation is:
    log%282%2C+%28x-3%29%29+=+2-log%282%2C+%28x%29%29
    If so, then there are no exponents in this equation!!
Please re-post and...
  • include the instructions
  • don't use the exponent character, "^" when posting logs. Either...
    • use some English to help describe the logs, like "base 2 log of (x-3)"
      Or...
    • Try to learn algebra.com's syntax for formulas. Click on the "Show source" link above to see what I typed to get those logs to look like they do here.