SOLUTION: Okay, so I'm given the problem: Write the expression as a single logarithm with the coefficient of 1. (7/3)logn(7y) + (2/5)logn(49y^2) Now I know the first step is to put

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Okay, so I'm given the problem: Write the expression as a single logarithm with the coefficient of 1. (7/3)logn(7y) + (2/5)logn(49y^2) Now I know the first step is to put       Log On


   

Question 823449: Okay, so I'm given the problem:
Write the expression as a single logarithm with the coefficient of 1.
(7/3)logn(7y) + (2/5)logn(49y^2)
Now I know the first step is to put the fractions in front of the log into exponent form so you get:
logn(7y)^(7/3) + logn(49y^2)^(2/5)
But after that, I'm not quite sure what to do because of the y ^2 in the second phrase of the problem. From what I have been doing in my lessons you can't combine the 7y and the (49y^2) right? I'm not sure what to do for the next step. Thanks for your help!!!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Rules of Logarithms:

    | Applies to this question

  |Applies to this question

     







(7/3)logn(7y) + (2/5)logn(49y^2) 

 Now I know the first step is to put the fractions in front of the log into exponent form so you get: 

 log%28n%2C%28%287y%29%5E%287%2F3%29%29%29+%2B+log%28n%2C%28%2849y%5E2%29%5E%282%2F5%29%29%29    | Applied Rule.  Good Work

log%28n%2C%28%287y%29%5E%287%2F3%29%28%287%5E2%29%28y%5E2%29%29%5E%282%2F5%29%29%29    | Applied Rule

Add  Exponents of Like terms to finish  |Note: 7%2F3+%2B+4%2F5+=+47%2F15