SOLUTION: the area of the rectangle is x^3 -2x^2 -5x+6 square feet. If its length is x-3 feet, what is its width?

Algebra ->  Rectangles -> SOLUTION: the area of the rectangle is x^3 -2x^2 -5x+6 square feet. If its length is x-3 feet, what is its width?      Log On


   

Question 823405: the area of the rectangle is x^3 -2x^2 -5x+6 square feet. If its length is x-3 feet, what is its width?
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
Since area = L * W
x^3 -2x^2 -5x+6 = ( x-3 )( W )
and
W = %28x%5E3+-2x%5E2+-5x%2B6%29+%2F+%28+x-3+%29
Here is the long division.

_________x%5E2%2Bx-2
(x-3)|x%5E3+-2x%5E2+-5x%2B6+
_____x%5E3-3x%5E2
________x%5E2-5x
________x%5E2-3x
___________-2x%2B6
___________-2x%2B6
________________0
So the width is x%5E2%2Bx-2.