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Question 823380: Find the equation, in standard form, of the line perpendicular to -5x+3y=3 that passes through the points (-8,-9). Write the equations in standard form.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
-5x + 3y = 3
3y = 5x + 3
y = (5/3)x + 1
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perp lines have negative reciprocal slopes, so the perp slope = -3/5 = -0.6
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perp line contains (-8,-9)
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to solve the linear equation, copy and paste this (given point and perp slope):
-8,-9,-0.6
into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
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x-intercept = (-23, 0)
y-intercept = (0, -13.8)
slope = -0.6
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answer:
the slope-intercept form:
y = -0.6x - 13.8
the standard form:
0.6x + y = -13.8
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