Question 823199: a father is now three times as old as his son. twelves years ago he was six times as old as his son. find the present age of each. Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
x = 3y
x - 12 = 6(y - 12)
---
x = 3y
x - 12 = 6y - 72
---
put the system of linear equations into standard form
---
x - 3y = 0
x - 6y = -60
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
answer:
x= father = 60
y= son = 20
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
