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| Question 823171:  1. x^2+y^2=16         y=-x^2-4
 2. x^2-y^2=61        x^2-y^2=11
 The directions are solve the system of liner or non-linear equations but im not sure how
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! 1. x^2+y^2=16 y=-x^2-4 -------
 x^2 = y-4
 Substitute for "x^2" and solve for "y":
 y-4 + y^2 = 16
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 y^2 + y - 20 = 0
 Factor:
 (y+5)(y-4) = 0
 y = -5 or y = 4
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 Solve for "x":
 x^2 = y-4
 If y = -5, x^2 = -9
 Therefore y = -5 is extraneous.
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 If y = 4, x^2 = 4-4 = 0
 Then x = 0
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 Solution:: (0,4)
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 2.
 x^2-y^2=61
 x^2-y^2=11
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 Subtract to get:
 0 = 50
 That is a contradiction.
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 There are no solutions.
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 Cheers,
 Stan H.
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