SOLUTION: "7% of al switches produced are defective. if 200 switches are selected at random, what us the probability that more than 20 will be defective?" I know how to do it if it's exact

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Question 823139: "7% of al switches produced are defective. if 200 switches are selected at random, what us the probability that more than 20 will be defective?"
I know how to do it if it's exactly 20 but no matter how I try I cannot figure this out

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
"7% of al switches produced are defective. if 200 switches are selected at random,
what us the probability that more than 20 will be defective?"
BINOMIAL Distribution P(x) = nCx* p%5Ex%2Aq%5E%28n-x%29
where p and q are the probabilities of success and failure respectively.
In this case p = .07 & q = .93 & n = 200 nCx = n%21%2F%28x%21%28n-x%29%21%29
P(20) =(200C20)(.07)^20(.93)^180 Or binompdf(200, .07, 20)on calculator
Recommend using Your TI calculator for cumulative probabilities
and/or stattrek.com as an excellent reference.
P(x>20) = 1 - P(x ≤ 20) = 1 - binomcdf(200, .07, 20) on a Ti calculator
Without a Calculator: 1 - [ P(0) + P(1) + P(2) .... + P(20)]
Tedious, but can be done.
Again: stattrek.com is an excellent reference (also has calculators)