SOLUTION: John gives smith as many coins Smith has.
Smith then gives John as many coins as John has remaining.
Now John has 36 coins and Smith has 42 coins.
How many coins that each of th
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-> SOLUTION: John gives smith as many coins Smith has.
Smith then gives John as many coins as John has remaining.
Now John has 36 coins and Smith has 42 coins.
How many coins that each of th
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Question 823025: John gives smith as many coins Smith has.
Smith then gives John as many coins as John has remaining.
Now John has 36 coins and Smith has 42 coins.
How many coins that each of them have to begin with?
You can put this solution on YOUR website! Start:
John has "J" coins.
Smith has "S" coins.
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John gives smith as many coins as Smith has.
Now:
John has J-S coins.
Smith has 2S
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Smith then gives John as many coins as John has remaining
Then:
John has J-S+[J-(J-S)] = J
Smith has 2S - [J-(J-S)] = S
Now John has 36 coins and Smith has 42 coins.
How many coins that each of them have to begin with?
John has "J" coins = 36
Smith has "S"coins = 42
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Cheers,
Stan H.
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