|
Question 822869: Find the vertex of the parabola y^2 +8x - 6y +1=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the vertex of the parabola y^2 +8x - 6y +1=0
complete the square:
(y^2-6y+9)+8x=-1+9
(y-3)^2=-8x+8=-8(x-1)
(y-3)^2=-8(x-1)
This is a parabola that opens leftward.
Its basic equation:(y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of vertex
For given parabola:
vertex(1,3)
|
|
|
| |
