SOLUTION: kindly answer this using systems of linear equations. (w/solutions if possible) Thank you!
x^2+y^2-2x+2y-3=0
x^2+y^2-x+y-4=0
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Systems-of-equations
-> SOLUTION: kindly answer this using systems of linear equations. (w/solutions if possible) Thank you!
x^2+y^2-2x+2y-3=0
x^2+y^2-x+y-4=0
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Question 822605: kindly answer this using systems of linear equations. (w/solutions if possible) Thank you!
x^2+y^2-2x+2y-3=0
x^2+y^2-x+y-4=0 Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! They are not linear.
They are two circles.
x^2+y^2-2x+2y-3=0
(x-1)^2+(y+1)^2=5
x^2+y^2-x+y-4=0
(x-1/2)^2+(y+1/2)^2=9/2
y=x-1
x = -1, y = -2
x = 2, y = 1
