Question 822560: Find the equation ,in the form y = ax^2 + bx + c,of the parabola which passes through the points(-3,0) and (1,-16).
Found 2 solutions by Alomelo, Alan3354:
Answer by Alomelo(2)   (Show Source):
You can put this solution on YOUR website! For (-3,0)
we write 0=(-3)^2+b(-3)+C, So, 3b-c=9........(i)
and for(1,-16), So b+c=-17......................(ii)
So (i)+(ii) we get b=-2
So put this into equation(ii) we get c=-15
so ultimetly the equation is: y=x^2-2x-15.
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! Find the equation ,in the form y = ax^2 + bx + c,of the parabola which passes through the points(-3,0) and (1,-16).
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2 points is not sufficient to define a parabola, 3 are needed.
An infinite number of parabolas can be found that pass thru 2 points.
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