Question 822508: The plans for an apartment complex provided for 440 apartments, with each apartment having one, two, or three bedrooms. There were to be 30 more three-bedroom than one-bedroom apartments, and the number of two-bedroom apartments was to be 10 less than 3 times the number of one-bedroom apartments. How many apartments of each type were in the plans?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
x + y + z = 440
z = x + 30
y = 3x - 10
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put the system of linear equations into standard form
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x + y + z = 440
x - z = -30
3x - y = 10
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answer:
x= one-room apts = 84
y= two-room apts = 242
z= three-room apts = 114
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