SOLUTION: The length of a rectangle is 1 inch less than twice the width, and the perimeter is 40 inches. Find the width and the length.
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Question 822495: The length of a rectangle is 1 inch less than twice the width, and the perimeter is 40 inches. Find the width and the length. Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
x = 2y - 1
2x + 2y = 40
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put the system of linear equations into standard form
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x - 2y = -1
2x + 2y = 40
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x= length = 13 inch
y= width = 7 inch
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