SOLUTION: please help.
The length of a rectangle in 9in. more than twice its width. If the peremiter of the rectangle is 48in.,find the width of the rectangle.
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The length of a rectangle in 9in. more than twice its width. If the peremiter of the rectangle is 48in.,find the width of the rectangle.
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Question 82229: please help.
The length of a rectangle in 9in. more than twice its width. If the peremiter of the rectangle is 48in.,find the width of the rectangle. Answer by neta(14) (Show Source):
You can put this solution on YOUR website! the eqn for the problem is
let the width be x, the perimeter is give as 48
perimeter=2(l+b)
therefor L=9+2x
48=2((2x+9)+x)
48=4x+18+2x
take 18 over
48-18=6x
30=6x
x=30/6
x=5
therefore the width is 5in.
if you doubt your answer you cn always fix it back to the eqn to test your answer
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