SOLUTION: The difference of two nbers is 5. Five times the lesser number is 9 greater than the greater number. What are the numbers?

Click here to see ALL problems on Systems-of-equations

Question 822237: The difference of two nbers is 5. Five times the lesser number is 9 greater than the greater number. What are the numbers?
Found 2 solutions by TimothyLamb, stanbon:
Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website!
---
y - x = 5
5x = y + 9
---
put the system of linear equations into standard form
---
-x + y = 5
5x - y = 9
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
answer:
x= 3.5
y= 8.5
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The difference of two nbers is 5. Five times the lesser number is 9 greater than the greater number. What are the numbers?
---------------------
Equations:
x - y = 5
5y = x+5
----------
Substitute for "x" and solve for "y"::
5y = y+5+5
-------
5y = y+10
4y = 10
y = 5/2
-------------
Solve for "x"
x - y = 5
x -(5/2) = 5
x = 5/2
-----------------
Cheers,
Stan H.
=============