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Question 822221: [ solve these quadratics ]
x^2-8x+16=0
5x^2+20x+21=0
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
x^2 - 8x + 16 = 0
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the above quadratic equation is in standard form, with a=1, b=-8, and c=16
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 -8 16
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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answer:
this quadratic has real roots, (its two x-intercepts), the roots are:
x = 4
x = 4
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5x^2 + 20x + 21 = 0
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the above quadratic equation is in standard form, with a=5, b=20, and c=21
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
5 20 21
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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answer:
this quadratic has complex roots, (these are NOT x-intercepts), the roots are:
x = -2 + (0.447213595)i
x = -2 - (0.447213595)i
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
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