SOLUTION: A 5% salt solution is mixed with a 10% salt solution. How many milliliters of each solution are needed to obtain 400 milliliters of an 8% solution?
Question 822053: A 5% salt solution is mixed with a 10% salt solution. How many milliliters of each solution are needed to obtain 400 milliliters of an 8% solution? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
5x + 10y = 8(400)
x + y = 400
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5x + 10y = 3200
x + y = 400
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answer:
x= 160 ml of 5%
y= 240 ml of 10%
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