SOLUTION: Consider these functions: y= 2x-13/x-5 and y= 3x+11/x+3 a. Rewrite each rational function to show how it is a transformation of y= 1/x b. describe the transformation of the graph

Algebra ->  Rational-functions -> SOLUTION: Consider these functions: y= 2x-13/x-5 and y= 3x+11/x+3 a. Rewrite each rational function to show how it is a transformation of y= 1/x b. describe the transformation of the graph      Log On


   



Question 822022: Consider these functions: y= 2x-13/x-5 and y= 3x+11/x+3
a. Rewrite each rational function to show how it is a transformation of y= 1/x
b. describe the transformation of the graph of y= 1/x that will produce graphs of the equation

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
First of all, please put parentheses around numerators and denominators, especially if they are not just a positive integer or variable. What you posted meant:
y=+2x-13%2Fx-5
which is not a transformation from y = 1/x. What you meant must have been
y=+%282x-13%29%2F%28x-5%29
which should be posted as:
y= (2x-13)/(x-5)

For part a we will start by using long division to divide:
               2
        __________
x - 5  / 2x - 13
         2x - 10
        --------
              -3
So now we have:
y+=+2+%2B+%28-3%29%2F%28x-5%29
Now we'll move some things around to make the transformations more obvious:
y+=+%28-3%29%2F%28x-5%29+%2B+2
y+=+%28-3%29%2A%281%2F%28x-5%29%29+%2B+2
Let f(x) = 1/x. Then we can write:
y+=+%28-3%29%2A%28f%28x-5%29%29+%2B+2

Part b. The transformations:
  • The f(x-5) indicates a phase/horizontal shift/translation to the right by 5 units.
  • The +2 indicates a vertical shift/translation of up 2 units.
  • The minus of -3 indicates a reflection across the horizontal axis (which has been moved up to y = 2 by the vertical shift).
  • The 3 of -3 indicates a vertical stretching by a factor of 3.
Here's what the graphs look like (your function in red, f(x) = 1/x in green):
graph%28600%2C+600%2C+-3%2C+9%2C+-4%2C+8%2C+2%2B%28-3%29%2F%28x-5%29%2C+1%2Fx%29

I'll leave the other function for you to do.