SOLUTION: Larry spent 1/2 of his money on a camera and 1/8 on a radio. The camera cost $120 more that the radio. How much money did he start with?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Larry spent 1/2 of his money on a camera and 1/8 on a radio. The camera cost $120 more that the radio. How much money did he start with?      Log On


   

Question 821817: Larry spent 1/2 of his money on a camera and 1/8 on a radio.
The camera cost $120 more that the radio.
How much money did he start with?
Found 2 solutions by TimothyLamb, richwmiller:
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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x = starting cash
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the camera:
z = (1/2)x
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the radio:
y = (1/8)x
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given: the camera is $120 more than the radio
z = y + 120
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y + 120 = (1/2)x
y = (1/8)x
---
put the system of linear equations into standard form
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0.5x - y = 120
0.125x - y = 0
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
x= 320
y= 40
---
answer:
starting cash = $320
camera = $160
radio = $40
---
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---
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---
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Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
c=1/2x,
r=1/8x,
c=r+180
c = 240, r = 60, x = 480
he started with $480
he spent $60 on the radio and $240 on the camera.