SOLUTION: [ Company A rents video for $4.50 each and has no membership fee. Company B rents videos for $2 each, but has a membership fee of $10. A) Graph both lines using a table of value

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: [ Company A rents video for $4.50 each and has no membership fee. Company B rents videos for $2 each, but has a membership fee of $10. A) Graph both lines using a table of value      Log On


   



Question 821803: [ Company A rents video for $4.50 each and has no membership fee. Company B rents videos for $2 each, but has a membership fee of $10.
A) Graph both lines using a table of value
B) state the point of intersection?
C) Explain what the point of intersection means in this problem .
D) which company offers best rate for renting 3 videos ? explain why.
E) which company offers the best rate for renting 7 videos? Explain why.

Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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Company A:
y = 4.5x
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Company B:
y = 2x + 10
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y = 4.5x
y = 2x + 10
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put the system of linear equations into standard form
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4.5x - y = 0
2x - y = -10
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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the solution (the point of intersection):
x= 4 videos
y= $18 to rent 4 videos
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the solution to the system of equations is the point of intersection of the two linear equations.
at that point, it costs exactly the same ($18) to rent 4 videos from either company.
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renting 3 videos:
y = 4.5*3 = $13.50
y = 2*3 + 10 = $16.00
company A is cheaper for 3 videos because the membership fee of company B divided over 3 videos (10/3 = $3.33) is more than the difference in video rental rates ($4.50 - $2.00 = $2.50)
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renting 7 videos:
y = 4.5*7 = $31.50
y = 2*7 + 10 = $24.00
company B is cheaper for 7 videos because the membership fee of company B divided over 7 videos (10/7 = $1.43) is less than the difference in video rental rates ($4.50 - $2.00 = $2.50)
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Solve systems of linear equations up to 6-equations 6-variables:
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