SOLUTION: the length of a rectangle is 8 in more than twice its width. if the perimeter of the rectangle is 58 in, find the width of the rectangle
a)6 in
b)7 in
c)8 in
d)9 in
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-> SOLUTION: the length of a rectangle is 8 in more than twice its width. if the perimeter of the rectangle is 58 in, find the width of the rectangle
a)6 in
b)7 in
c)8 in
d)9 in
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Question 82156: the length of a rectangle is 8 in more than twice its width. if the perimeter of the rectangle is 58 in, find the width of the rectangle
a)6 in
b)7 in
c)8 in
d)9 in Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! L=2W+8
P=2L+2W
58=2(2W+8)+2W
58=4W+16+2W
58=6W+16
6W=58-16
6W=42
W=42/6
W=7 ANSWER IS C) 7 INCHES.
PROOF
58=2(2*7+8)+2*7
58=2(14+8)+14
58=2*22+14
58=44+14
58=58
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