Question 821556: A ball is thrown in the air from a height of 4 ft with an initial velocity of 35 ft/sec.
i) When does the ball hit the ground?
ii) What is the maximum height?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
equation of motion:
h(t) = -16tt + 35t + 4
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the above quadratic equation is in standard form, with a=-16, b=35, and c=4
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
-16 35 4
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the two real roots (i.e. the two x-intercepts), of the quadratic are:
t = -0.108867588
t = 2.29636759
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negative time doesn't make sense for this problem so use the positive root
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the parabola has a vertex maximum at: ( t= 1.09375, h(t)= 23.140625 )
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answer:
ball hits the ground 2.29636759 seconds after being thrown
ball reaches a max height of 23.140625 ft
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