SOLUTION: Sir/Madam Please help me solve the problem given below The average of 8 numbers is 12.If one of them exceeds the average of remaining by 8.The number is ? Thank you

Let number be N

Then sum, excluding N is: 96 – N

Average of numbers, excluding N = 

Therefore, 

7N = 96 – N + 56 ------ Multiplying by LCD, 7

7N + N = 96 + 56

8N = 152

N, or number = , or 

You can do the check!! 



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