SOLUTION: if the perimeter of a rectangle is 220, lenght is 10 times greater than width, what will be the width?

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Question 821479: if the perimeter of a rectangle is 220, lenght is 10 times greater than width, what will be the width?
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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2x + 2y = 220
x = 10y
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put the system of linear equations into standard form
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2x + 2y = 220
x - 10y = 0
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x= length = 100
y= width = 10
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