SOLUTION: the perimeter of a rectangle is 68 in. The length is 2 less than 3 times the width. find the dimensions of the rectangle

Algebra ->  Rectangles -> SOLUTION: the perimeter of a rectangle is 68 in. The length is 2 less than 3 times the width. find the dimensions of the rectangle       Log On


   



Question 821399: the perimeter of a rectangle is 68 in. The length is 2 less than 3 times the width. find the dimensions of the rectangle

Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
---
2x + 2y = 68
x = 3y - 2
---
put the system of linear equations into standard form
---
2x + 2y = 68
x - 3y = -2
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
answer:
x= L = 25 in
y= w = 9 in
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php