SOLUTION: x^2-3x^5>10

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Question 821307: x^2-3x^5>10
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-3x%5E5%3E10
-3x%5E5%2Bx%5E2-10%3E0
3x%5E5-x%5E2%2B10%3C0
A graphing calculator would tell you that
f%28x%29=3x%5E5-x%5E2%2B10=0 happens for x=-1.2311 (rounded),
with the 3x%5E5-x%5E2%2B10%3C0 only for x%3C-1.2311 .
Before graphing calculators, I would have calculated the derivative as
df%2Fdx=15x%5E4-2x=15x%28x%5E3-2%2F15%29=
Since the last factor is always positive, the zeros of the derivative are at x=0 and at x=root%283%2C2%2F15%29 .
The derivative is negative in between those two values of x ,
meaning that is an interval where f%28x%29 decreases.
For other values of x , the derivative is positive and the function increases.
At x=0 where f%280%29=10 we have a maximum of f%28x%29 ,
and at x=root%283%2C2%2F15%29 , a minimum of f%28x%29 , where f%28x%29%3E0 .
Since f%28-2%29=-90 and f%28-1%29=6 ,
The value of x that makes f%28x%29=0 is in between, -2%3Cx%3C-1 .
At that point we would try guess-and-check values in between, aiming to get closer limits on x, maybe going through
-1.5%3Cx%3C-1 , -1.5%3Cx%3C-1.2 , -1.3%3Cx%3C-1 and so on, until I got a close enough approximation.