SOLUTION: please help. The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the pereminter is 29cm, find the length of one of t

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Question 82129: please help.
The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the pereminter is 29cm, find the length of one of the equal legs.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
The length of one of the equal sides can be written as:
4x-8 where x is the length of the base.
The perimeter is equal to the sum of the lengths of the three legs of the triangle...so:
(4x-8)+(4x-8)+x = 29cm Simplify and solve for x.
9x-16 = 29 Add 16 to both sides.
9x = 45 Divide both sides by 9
x = 5 cm This is the length of the base.
4x-8 = 4(5)-8 = 20-8 = 12 cm This is the length of one of the equal legs.