SOLUTION: Twenty-six slips of paper are each marked with a different letter of the alphabet and placed in a basket. A slip is pulled out, its letter recorded (in the order in which the slip

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Question 821284: Twenty-six slips of paper are each marked with a different letter of the alphabet and placed in a basket. A slip is pulled out, its letter recorded (in the order in which the slip was drawn), and the slip is replaced. This is done 4 times. find the probability that a word with no repetition of letter is formed.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
There are 26%5E4 possible words that could be formed that way, all equally probable.
The number of words that can be formed without repetition of letters is
26%2A25%2A24%2A23 .
So in 26%2A25%2A24%2A23 out of 26%5E4 possible cases a word with no repetition of letter would be formed.
The probability that a word with no repetition of letter is formed is
(rounded)