SOLUTION: A bacteria culture started with 6500 bacteria and increased by 35% in the first 2 hours. How long does it take for the population to triple in size? I know I use Q(t)=6500e^t ...

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: A bacteria culture started with 6500 bacteria and increased by 35% in the first 2 hours. How long does it take for the population to triple in size? I know I use Q(t)=6500e^t ...      Log On


   

Question 821198: A bacteria culture started with 6500 bacteria and increased by 35% in the first 2 hours. How long does it take for the population to triple in size?
I know I use Q(t)=6500e^t ...but I keep getting wrong answers and only get 5 tries. Any help would be MUCH appreciated! Thank you!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

A bacteria culture started with 6500 bacteria and increased by 35% in the first 2 hours. 

 6500 + .35(6500) = 6500(1 + .35) = 1.35(6500)

 Q(t)=6500e^(kt) 

1.35(6500) = 6500e^(kt) 

   1.35+=+e%5E%28green%282%29k%29

   ln(1.35)/2 = k = .1501

 +Q%28t%29=Q%5B0%5De%5E%28.1501t%29 

How long does it take for the population to triple in size? Q%28t%29%2FQ%5B0%5D+=+3 

   +3+=+e%5E%28.1501t%29

 ln3/.1501 = t 

Note: Always important to use the assignment requirement for the proper amount of decimal points