Question 821128: the area of a triangle is 18 cm^2 and the altitude is 3 cm greater than the base. find the length of the base, to the nearest hundredth of a centimetre
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
18 = b(b + 3)/2
18 = bb/2 + 3b/2
(1/2)bb + (3/2)b - 18 = 0
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the above quadratic equation is in standard form, with a=0.5, b=1.5, and c=-18
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
0.5 1.5 -18
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the two real roots (i.e. the two x-intercepts), of the quadratic are:
b = 4.68465844
b = -7.68465844
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negative length doesn't make sense so use the positive root:
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answer:
base = 4.69 cm
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