SOLUTION: [ Joanne was shopping and received change worth $13. She received ten more dimes than nickels, and 22 more quarters than dimes. How many coins of each kind does she have? ]
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Question 821127: [ Joanne was shopping and received change worth $13. She received ten more dimes than nickels, and 22 more quarters than dimes. How many coins of each kind does she have? ] Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
z = y + 22
y = x + 10
5x + 10y + 25z = 1300
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put the system of linear equations into standard form
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y - z = -22
x - y = -10
5x + 10y + 25z = 1300
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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x= 10
y= 20
z= 42
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answer:
nickels = 10
dimes = 20
quarters = 42
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