| 
 
 
| Question 821081:  lighthouse is 10 km northwest of dock. A ship leaves the dock at 9 am and steams west at 12kph. at  what time will it be 8 km from the lighthouse
 Answer by TimothyLamb(4379)
      (Show Source): 
You can put this solution on YOUR website! --- LH:
 adj = hyp cos( 45 )
 x = 10 cos( 45 )
 x = 7.0711
 opp = hyp sin( 45 )
 y = 10 cos( 45 )
 y = 7.0711
 LH point: (7.0711, 7.0711)
 ---
 ship at 8 km from LH
 point = (x, 0)
 ---
 distance formula when ship is at 8 km from LH
 8 = sqrt( (x - 7.0710678)(x - 7.0710678) + (0 - 7.0710678)(0 - 7.0710678) )
 8 = sqrt( (xx - 14.142136x + 50) + 50 )
 64 = xx - 14.142136x + 100
 xx - 14.142136x + 36
 ---
 the above quadratic equation is in standard form, with a=1, b=-14.142136, and c=36
 ---
 to solve the quadratic equation, by using the quadratic formula, copy and paste this:
 1 -14.142136 36
 into this solver: https://sooeet.com/math/quadratic-equation-solver.php
 ---
 the two real roots (i.e. the two x-intercepts), of the quadratic are:
 x = 10.8127257
 x = 3.32941026
 ---
 distance: 8 km from LH when 3.33 km from the dock (along the ship's west course)
 time = 3.33/12 = 0.2775 * 60 = 16.65 min
 ---
 answer:
 at 9:17 AM the ship is 8 km from the lighthouse
 ---
 Solve and graph linear equations:
 https://sooeet.com/math/linear-equation-solver.php
 ---
 Solve quadratic equations, quadratic formula:
 https://sooeet.com/math/quadratic-formula-solver.php
 ---
 Solve systems of linear equations up to 6-equations 6-variables:
 https://sooeet.com/math/system-of-linear-equations-solver.php
 | 
  
 | 
 |