SOLUTION: There are 3 brothers all with different ages.
The oldest is twice as old as the youngest.
The middle child is one year younger than the oldest.
The sum of their ages is 39.
Fin
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The oldest is twice as old as the youngest.
The middle child is one year younger than the oldest.
The sum of their ages is 39.
Fin
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Question 821071: There are 3 brothers all with different ages.
The oldest is twice as old as the youngest.
The middle child is one year younger than the oldest.
The sum of their ages is 39.
Find how old each brother is. Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! z = 2x
y = z - 1
x + y + z = 39
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put the system of linear equations into standard form
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2x - z = 0
y - z = -1
x + y + z = 39
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x= 8
y= 15
z= 16
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