SOLUTION: An Architect designs the front view of a house with a gable roof that has 45 - 45 - 90 degree triangle. The overhangs are 0.5 meter each from the exterior walls, and the width of t

Algebra ->  Triangles -> SOLUTION: An Architect designs the front view of a house with a gable roof that has 45 - 45 - 90 degree triangle. The overhangs are 0.5 meter each from the exterior walls, and the width of t      Log On


   

Question 821042: An Architect designs the front view of a house with a gable roof that has 45 - 45 - 90 degree triangle. The overhangs are 0.5 meter each from the exterior walls, and the width of the house is 16 meters. what should the side length of the triangle be? Round your answer to the nearest meter.
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
base = 0.5(2) + 16 = 17 m
base = hyp
hyp = sqrt( aa + bb )
a = b (isosceles)
hyp = sqrt( 2aa )
17 = sqrt( 2aa )
289 = 2aa
aa = 144.5
a = 12.020818 m
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answer:
each roof pitch should be 12 m long
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