Question 821030: Find the vertices, foci, and eccentricity of the ellipse of 2x^2 + 3y^2 = 6
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the vertices, foci, and eccentricity of the ellipse of
2x^2 + 3y^2 = 6
x^2/3 + y^2/2 = 1
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Given ellipse has a horizontal major axis with center at the origin (0,0)
Its standard form of equation:x^2/a^2+y^2/b^2=1, a>b
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a^2=3
a=√3
vertices:(0±a,0)=(0±√3,0)=(-√3,0) and (√3,0)
b^2=2
c^2=a^2-b^2=3-2=1
c=1
foci:(0±c,0)=(0±1,0)=(-1,0) and (1,0)
eccentricity=c/a=1/√3=√3/3
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