SOLUTION: If the perimeter of a triangle is 52m and the sides are 2x, x+7, and 3(x-1), how do I find the value of the xs?

Algebra ->  Triangles -> SOLUTION: If the perimeter of a triangle is 52m and the sides are 2x, x+7, and 3(x-1), how do I find the value of the xs?      Log On


   

Question 821024: If the perimeter of a triangle is 52m and the sides are 2x, x+7, and 3(x-1), how do I find the value of the xs?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Add up the sides and set them equal to the perimeter. Then solve for x.

S1 + S2 + S3 = P

2x + (x+7) + 3(x-1) = 52

2x+x+7+3x-3 = 52

6x+4 = 52

6x = 52-4

6x = 48

x = (48)/(6)

x = 8