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Question 820968: [ Find the x-intercept(s) and the coordinates of the vertex for the parabola y = x^2 + 2x - 15 ]
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
y = x^2 + 2x - 15
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the above quadratic equation is in standard form, with a=1, b=2, and c=-15
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 2 -15
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the two real roots (i.e. the two x-intercepts), of the quadratic are:
x = 3
x = -5
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the vertex is a minimum at: ( -1, -16 )
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