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Question 820912: [ Find all value of x such that the distance between (x,-9) and(3,-5) is 6. ]
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! 6 = sqrt( (x - 3)(x - 3) + (-9 + 5)(-9 + 5) )
36 = (x - 3)(x - 3) + (-4)(-4)
36 - 16 = xx - 6x + 9
20 = xx - 6x + 9
xx - 6x - 11 = 0
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the above quadratic equation is in standard form, with a=1, b=-6, and c=-11
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 -6 -11
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the two real roots (i.e. the two x-intercepts), of the quadratic are:
x = 7.47213595
x = -1.47213595
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answer:
either value of x satisfies the requirement:
x = 7.47213595
x = -1.47213595
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