SOLUTION: Find all solutions to the equation over the interval [0,2pie): sqrt(2)sin3x+1=0
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Question 820889
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Find all solutions to the equation over the interval [0,2pie):
sqrt(2)sin3x+1=0
Answer by
lwsshak3(11628)
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Find all solutions to the equation over the interval [0,2pie):
sqrt(2)sin3x+1=0
√2sin(3x)+1=0
sin(3x)=-1/√2=-√2/2
3x=5π/4,7π/4 (In quadrants III and IV where sin<0)
x=5π/12,7π/12