SOLUTION: {{{7x^2+11x-4=14-4x}}} This is as far as I got: {{{7x^2+11x-4-14+4x}}} {{{7x^2+15x-18=0}}} I am stuck after this and do not know what to do next. Can you help me?

Algebra ->  Exponents -> SOLUTION: {{{7x^2+11x-4=14-4x}}} This is as far as I got: {{{7x^2+11x-4-14+4x}}} {{{7x^2+15x-18=0}}} I am stuck after this and do not know what to do next. Can you help me?      Log On


   

Question 820778: 7x%5E2%2B11x-4=14-4x This is as far as I got: 7x%5E2%2B11x-4-14%2B4x 7x%5E2%2B15x-18=0 I am stuck after this and do not know what to do next. Can you help me?
Answer by Edwin McCravy(20065) About Me  (Show Source):
You can put this solution on YOUR website!
7x² + 15x - 18 = 0

You have to factor that.

There is only one way to break up 7x² and that is 7x and x:

(7x  )(x  ) = 0

But there are several ways to break up -18 = -18·1 = -9·2 = -6·3

A little trial and error by FOILing back to see if you get the
preceding trinomial, gives:

(7x-6)(x+3) = 0

Set each factor = 0

7x-6 = 0;  x+3 = 0
  7x = 6;    x = -3
   x = 6%2F7

Two solutions:  6%2F7 and -3

Edwin