SOLUTION: I need to know how these two can be solved. 1.((p^-6)(q^2))^7/6 2. square root of 2 plus 5/square root of 3 minus 8

Algebra ->  Radicals -> SOLUTION: I need to know how these two can be solved. 1.((p^-6)(q^2))^7/6 2. square root of 2 plus 5/square root of 3 minus 8       Log On


   

Question 82073This question is from textbook Experiencing Introdutory and Intermediate Algebra
: I need to know how these two can be solved.
1.((p^-6)(q^2))^7/6


2. square root of 2 plus 5/square root of 3 minus 8
This question is from textbook Experiencing Introdutory and Intermediate Algebra

Answer by blizz86(3) About Me  (Show Source):
You can put this solution on YOUR website!
1. the way you stated your question doesnt make sense
2. square root of 2 plus 5/square root of 3 minus 8
2^2 + 5/3^2 - 8
so thats 4 + 5/9 - 8
compute that and theirs your answer