SOLUTION: Me.sheen rode a distance of 12miles out into the country on a bicycle and returned on foot. His rate of the bicycle was 4 times his rate on foot. He spent 5 hours on the entire tri

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Question 820558: Me.sheen rode a distance of 12miles out into the country on a bicycle and returned on foot. His rate of the bicycle was 4 times his rate on foot. He spent 5 hours on the entire trip. Find his rate of walking.
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Me.sheen rode a distance of 12miles out into the country on a bicycle and returned on foot. His rate of the bicycle was 4 times his rate on foot. He spent 5 hours on the entire trip. Find his rate of walking.
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Out DATA:
distance = 12 miles ; rate = x mph ; time = d/r = 12/x hrs
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Back DATA:
distance = 12 miles ; rate = 4x mph ; time = d/r = 12/4x hrs
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Equation:
time + time = 5 hours
12/x + 12/4x = 5
4*12 + 12 = 20x
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20x = 60
x = 3 mph (walking rate)
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +r+ = his rate on foot
+4r+ = his rate on a bicycle
Let +t+ = his time in hours on foot
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Equation for walking:
(1) +12+=+r%2At+
Equation for biking:
(2) +12+=+4r%2A%28+5+-+t+%29+
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(1) +t+=+12%2Fr+
and
(2) +12+=+20r+-+4r%2At++
Substitute (1) into (2)
(2) +12+=+20r+-+4r%2A%2812%2Fr%29++
(2) +12+=+20r+-+48+
(2) +20r+=+60+
(2) +r+=+3+
His rate of walking was 3 mi/hr
check:
(1) +12+=+3%2At+
(1) +t+=+4+
and
(2) +12+=+4%2A3%2A%28+5+-+t+%29+
(2) +12+=+12%2A%28+5+-+t+%29+
(2) +12+=+60+-+12t+
(2) +12t+=+60+-+12+
(2) +12t+=+48+
(2) +t+=+4+
OK