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Question 820441: How to write an equation of the line that passes through (5,-2) and is perpendicular to the line y=-6x+1
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! ---
get slope of original line from its equation: y = -6x + 1
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the equation was given in slope-intercept form: y = mx + b
so:
m is the slope = -6
b is the y-intercept = 1
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perpendicular lines have negative reciprocal slopes:
so the slope of the perp line = 1/(-m) = 1/6 = 0.166666
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copy and paste this (the given point and the slope of the perp line):
5, -2, 0.166666
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into the "Point-Slope form: x1 y1 m" input box of this solver:
https://sooeet.com/math/linear-equation-solver.php
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get the slope and the y-intercept of the perp line from the solver:
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slope of perp line = 0.166666 = 1/6
y-intercept of perp line = -2.83333
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answer:
write the equation of the perp line in slope-intercept form:
y = (0.166666x - 2.83333
y = (1/6)x - 51/18
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Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
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