SOLUTION: The average score for all pro golfers for a particular course has a mean of 70 and a
standard deviation of 3.0. Suppose that 36 pro golfers played a famous California golf
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standard deviation of 3.0. Suppose that 36 pro golfers played a famous California golf
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Question 820420: The average score for all pro golfers for a particular course has a mean of 70 and a
standard deviation of 3.0. Suppose that 36 pro golfers played a famous California golf
course today. Find the probability that the average score of the 36 golfers exceeded 71.
You can put this solution on YOUR website! The average score for all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0.
Suppose that 36 pro golfers played a famous California golf
course today.
Find the probability that the average score of the 36 golfers exceeded 71.
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z(71) = (71-70)/[3/sqrt(36)] = 1/(1/2) = 2
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P(x > 71) = P(z > 2) = 0.0228
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Cheers,
Stan H.
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