SOLUTION: I need your help on logarithms: 3/4loga(p^2q^8)-1/2loga(p^5q^2). Please help me!

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Question 820404: I need your help on logarithms: 3/4loga(p^2q^8)-1/2loga(p^5q^2). Please help me!
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3/4loga(p^2q^8)-1/2loga(p^5q^2)
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= loga[(p^2q^8)^(3/4) / (p^5q^2)^(1/2)]
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= loga[(p^(3/2)*q^6) / (p^(5/2)*q)]
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= loga[q^5/p]
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Cheers,
Stan H.
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

%283%2F4%29log%28a%2C%28p%5E2q%5E8%29%29+-%281%2F2%29log%28a%2C%28p%5E5q%5E2%29%29   

  log%28a%2C+%28p%5E2q%5E8%29%5E%283%2F4%29%2F%28p%5E5q%5E2%29%5E%281%2F2%29++%29

 log%28a%2C+%28p%5E%286%2F4%29q%5E%2824%2F4%29%2F%28p%5E%285%2F2%29q%5E1%29+%29+%29   |%28a%5Ep%29%5Eq+=+a%5E%28p%2Aq%29

 log%28a%2C+q%5E%285%29%2Fp%5E%281%29%29 =  log%28a%2C+q%5E%285%29%2Fp%29













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