the sum of the digits of a number of three digits is 18.
h+t+u = 18
if the number is divided by the sum of the ten's and hundred digits the quotient is 38 the remainder is 1.
Dividend = (Quotient)(Divisor) + Remainder
100h+10t+u = 38(t+h) + 1
100h+10t+u = 38t+38h+ 1
62h-28t+u = 1
if 99 is added to the number the digits will be reversed.
100h+10t+u + 99 = 100u+10t+h
99h-99u = -99
h-u = -1
Solve the system of three equations in three unknowns:
h+ t+u = 18
62h-28t+u = 1
h -u = -1
Get h=4, t=9, u=5, number = 495
Edwin
