SOLUTION: At 9:00 am a truck leaves the yard traveling west at a rate of 40 mph. At 11:00 am a second truck leaves along the same route, traveling at 50mph. When will the second truck catch

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Question 820173: At 9:00 am a truck leaves the yard traveling west at a rate of 40 mph. At 11:00 am a second truck leaves along the same route, traveling at 50mph. When will the second truck catch up to the first?

Found 2 solutions by stanbon, TimothyLamb:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
At 9:00 am a truck leaves the yard traveling west at a rate of 40 mph. At 11:00 am a second truck leaves along the same route, traveling at 50mph. When will the second truck catch up to the first?
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1st truck DATA:
rate = 40 mph ; time = x hrs ; distance = r*t = 40x miles
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2nd truck DATA:
rate = 50 mph ; time = x-2 hrs ; distance = r*t = 50(x-2) miles
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Equation:
distance = distance
40x = 50x-100
10x = 100
x = 10 hrs
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Meeting time:: 9:00AM + 10 hrs = 7:00PM
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Cheers,
Stan H.
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Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website!
head start:
s = d / t
d = s * t
d = 40 / (11 - 9)
d = 20 miles
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when the trucks meet they will both be distance D from the yard
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first truck:
D = 40(t + 2)
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second truck:
D = 50t
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D = 40(t + 2) = 50t
40t + 80 = 50t
10t = 80
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t = 8
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answer:
the trucks will meet at:
11 + 8
19:00 or 7:00 PM
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