Question 819985: [ the height of a certain projectile can be given by the following equation, [where t is in seconds and h(t) is in feet]: h(t)=144t-16t^2 At what time(s) does the projectile have a height of 224 ft? ]
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! h(t) = 144t - 16t^2
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-16t^2 + 144t = 224
-16t^2 + 144t - 224 = 0
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the above quadratic equation is in standard form, with a=-16, b=144, and c=-224
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to solve the quadratic equation, by using the quadratic formula, plug this:
-16 144 -224
into this: https://sooeet.com/math/quadratic-equation-solver.php
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the two real roots (i.e. the two x-intercepts), of the quadratic are:
t = 2
t = 7
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answer:
the projectile will have a height of 224 feet at:
2 seconds and 7 seconds
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